Message from Python discussions

November 2018

— I thought it's some big library 😅😅😜
but i found out it just a simple and small module

—

Hi folks.

I've done some research online to find out wether is possible or not to use a decorator for
checking a variable value, but apparently there's nothing easy to find.

The situation is this:

stop_when_6
Class PointlessExample():
    self.a = 2
    def increase():
        for self.a in range(12):
            self.a += 2
    def success():
        print("a is now 6")

Is there a way to create a stop_when_6 decorator that calls the PointlessExample.success method
when the a variable inside the increase method reaches 6 ?

What I've tried to do is this, but it's not working:

def stop_when_6():
    def wrapper(*args):
        if args[0].a == 6:
            args[0].success()

— But if you didn't get an answer, it's because:
1) you didn't make a smart question
2) you're asking for homework solution
3) your question can easily be solved using google
4) you're expecting someone to give you code that fits your needs magically

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— Wget is C, so it is just a ctypes wrapped or something

— No

— Edited

— It means:
0 - No, it's impossible
1 - No, this is not the way to ask questions here

?

— No, the example is convoluted and not a usecase for a decorator

— State the REAL thing you wanna do

— This is NOT hard, 1st write it in english: several digits optionally followed by a dash and several digits, and more of the same after a comma, endless times

Message permanent page

— Now write the regex, covering each part of the sentence

— \d+(-\d+)?(,\d+(-\d+)?)* ezpz