— Or foo(a++,a)
I think it is pretty straight-forward because in any argument eval order result will be the same, is not it?
— Oh, I got ya
— Yes but compiler decide order
— For the std is ub
— In this case the order doesn't matter
— Because std not declare order
— I do not write the code like this anyways, I'm a sane person
— A=1;foo(++a,a++);left to right:foo(2,2);Right to leftfoo(3,1);
— Pls fix this problem of code....int Value(int int)void main()int x=7;int y=4;Float Area;float value()float value(int a,int b)Area=A*A....
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— For starters you have no curly brackets