Message from JavaScript discussions

October 2017

— Pasting snippets in this chat will not help you learn or solve your problems


Okay thank you, all i need is add the myFunc2 function inside myFunc1(){request.done()} instead

myFunc1(); myFunc2();

— Well done

— You now now what is an async call and how to handle it

— Please stop using jQuery for your own projects and start using vanilla JS in order to learn real JS

— You will thank me later

— Actually the boss want me to do it with jquery, react and vue

— Sorry for you ^_^

— So he can compare it

— Yeah its hard but new things is good

— All of these should work

— It DOES mean that